Cricket Puzzle

#159

Sachin and Ganguly were batting against Zimbabwe to achieve a target of 205. 
India were 198/0, Sachin and Ganguly, both were 94 not out. 
Ganguly decided to wrap up the things in the next 3 balls (last balls of that over) 
but Sachin reminded him that he is on 94 and at non-strikers end. 
How could they both get to 100* and finishing the game in the next 3 balls ??

#sachinismn 

  Difficulty Level - 4/5

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  Solution : 

   Ganguly hits the 1st ball for a boundary(4 runs) and then on 2nd ball, runs 3. In between, the umpire calls ONE (RUN) SHORT i.e 2 runs awarded. 
So, Ganguly gets 6 runs and completes his Century. 
Also, as he ran 3 runs, Sachin will be on strike for the next ball. He hits a SIX and completes his Century.

2-Ball Solution :-
Ganguly hits the ball and runs 3, and fielder throws the ball which goes to the boundary as overthrows. In between, the umpire calls ONE (RUN) SHORT. 
So Total Runs = 3 (ran by batsmen) - 1 (One Short) + 4 (Overthrows).
So, Ganguly gets 6 runs and completes his Century. 
Also, as he ran 3 runs, Sachin will be on strike for the next ball. He hits a SIX and completes his Century, there by winning the match..