#156One of my friend, Shaun asked me to bring a wire from the market.
I was so confused at that moment, that I accidentally interchanged the feet and inches.
When he measured the wire that I brought, it was only 5/8 of the length required.
Can you tell, how much wire did Shaun originally asked to bring ??
Difficulty Level - 3/5
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Solution :
Shaun asked for 7 feet, 4 inches but I brought 4 feet, 7 inches.
If we label what Shaun asked for as A feet and B inches, which is (12 x A + B) inches, then he actually received B feet and A inches, which is (12 x B + A) inches. Which means that :
(5 ÷ 8) x (12 x A + B) = (12 x B + A)
Simplifying gives :
A = (91 ÷ 52) x B >>> A = (7 ÷ 4) x B
As B is the number of inches, it can only be between 1 and 12 and must give A as a whole number of feet.
B = 4 is the only possible value, which means that A = 7.
So, Shaun originally asked for 7 feet, 4 inches.
Solution :
Shaun asked for 7 feet, 4 inches but I brought 4 feet, 7 inches.
If we label what Shaun asked for as A feet and B inches, which is (12 x A + B) inches, then he actually received B feet and A inches, which is (12 x B + A) inches. Which means that :
(5 ÷ 8) x (12 x A + B) = (12 x B + A)
Simplifying gives :
A = (91 ÷ 52) x B >>> A = (7 ÷ 4) x B
As B is the number of inches, it can only be between 1 and 12 and must give A as a whole number of feet.
B = 4 is the only possible value, which means that A = 7.
So, Shaun originally asked for 7 feet, 4 inches.
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